X^2=-168x+x=6

Solution for X^2=-168x+x=6 equation:

X^2=-168X+X=6

We move all terms to the left:

X^2-(-168X+X)=0

We add all the numbers together, and all the variables

X^2-(-167X)=0

We get rid of parentheses

X^2+167X=0

a = 1; b = 167; c = 0;
Δ = b2-4ac
Δ = 1672-4·1·0
Δ = 27889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{27889}=167$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(167)-167}{2*1}=\frac{-334}{2}
=-167
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(167)+167}{2*1}=\frac{0}{2}
=0
$